Measurement of Time and Motion
Motion, Distance & Speed – Solved Numericals
Question 1
A car moves 150 m in 10 s. What is its speed in kilometres per hour (km/h)?
Click for solution
- Formula → Speed = Distance ÷ Time
- Put numbers → 150 m ÷ 10 s = 15 m/s
- Convert → 1 m/s = 3.6 km/h
- 15 m/s × 3.6 = 54 km/h
Speed = 54 km/h
Question 2
Runner A covers 400 m in 50 s. Runner B covers 400 m in 45 s.
(a) Find each runner’s speed.
(b) Who is faster and by how much?
Click for solution
Runner | Calculation | Speed (m/s) |
---|---|---|
A | 400 m ÷ 50 s | 8 |
B | 400 m ÷ 45 s | 8.89 |
Runner B is faster by 0.89 m/s (≈3.2 km/h).
Question 3
A train runs at 25 m/s. How long will it take to cover 360 km?
Click for solution
- Convert speed → 25 m/s × 3.6 = 90 km/h
- Time = Distance ÷ Speed = 360 km ÷ 90 km/h
- Time = 4 h
It takes 4 hours.
Question 4
A train travels 180 km in 3 h.
(i) Speed in km/h
(ii) Speed in m/s
(iii) Distance in 4 h at same speed
Click for solution
- (i) 180 km ÷ 3 h = 60 km/h
- (ii) 60 km/h ÷ 3.6 = 16.67 m/s
- (iii) 60 km/h × 4 h = 240 km
(i) 60 km/h (ii) 16.67 m/s (iii) 240 km
Question 5
The fastest horse runs 18 m/s. A train moves 72 km/h. Which is faster and by how much?
Click for solution
- Horse → 18 m/s × 3.6 = 64.8 km/h
- Difference → 72 − 64.8 = 7.2 km/h
Train is faster by 7.2 km/h (≈2 m/s).
Question 6
Explain, with examples, the difference between uniform and non-uniform motion.
Click for explanation
• Car on an empty highway keeps one steady speed → uniform motion.
• Car in city traffic speeds up, slows, stops → non-uniform motion.
Question 7
Fill the missing distance. The motion is uniform.
Time (s) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 |
---|---|---|---|---|---|---|---|---|
Distance (m) | 0 | 8 | 16 | 24 | 32 | ? | 48 | 56 |
Click for solution
- Speed = 8 m / 10 s = 0.8 m/s
- Distance at 50 s = 0.8 m/s × 50 s = 40 m
Missing distance = 40 m.
Question 8
A cyclist rides 60 km, 40 km, and 80 km in three successive hours.
(a) Is the motion uniform?
(b) Find the average speed.
Click for solution
- Different distances each hour → non-uniform motion.
- Total distance = 60 + 40 + 80 = 180 km.
- Total time = 3 h ⇒ Avg speed = 180 km ÷ 3 h = 60 km/h.
(a) Non-uniform (b) Average speed = 60 km/h
Question 9
Write three everyday examples of non-uniform motion.
Click for examples
1. Walking to school (stop at crossings).
2. Bus in city traffic.
3. Cycling on a busy road.
Question 10
Table of a walker’s journey:
Time (s) | 0 | 20 | 40 | 60 | 80 | 100 |
---|---|---|---|---|---|---|
Distance (m) | 0 | 10 | 23 | 39 | 95 | 131 |
(a) Is the speed uniform?
(b) Find average speed in m/s and km/h.
Click for solution
- Unequal jumps → speed is non-uniform.
- Average speed = Total distance ÷ Total time.
- 131 m ÷ 100 s = 1.31 m/s.
- 1.31 m/s × 3.6 ≈ 4.7 km/h.
(a) Non-uniform (b) 1.31 m/s (≈ 4.7 km/h)
Question 11
A 2000 m race must finish in 200 s.
The runner covers:
• first 500 m at 10 m/s
• next 500 m at 5 m/s
(a) Time left for last 1000 m?
(b) Required speed for last 1000 m?
(c) Average speed for whole race?
Click for solution
- First 500 m → 500 m ÷ 10 m/s = 50 s.
- Next 500 m → 500 m ÷ 5 m/s = 100 s.
- Time used = 150 s ⇒ Time left = 200 − 150 = 50 s.
- Required speed = 1000 m ÷ 50 s = 20 m/s.
- Average speed = 2000 m ÷ 200 s = 10 m/s (36 km/h).
(a) 50 s left (b) Need 20 m/s (c) Avg = 10 m/s
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