9th Standard Chapter 7 Motion NCERT Exercise Questions with Answers
Motion Class – 9th Standard Mode
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An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
Distance per lap
= π × 200 m ≃ 628.3 mTotal time
= 2 min 20 s = 140 s ⇒ laps = 140 ÷ 40 = 3.5Total distance
= 3.5 × 628.3 ≃ 2199.1 mDisplacement
= straight‐line from start to end. After 3½ laps you’re opposite the start ⇒ 200 m -
Joseph jogs from A to B (300 m) in 2 min 30 s, then 100 m back to C in 1 min. Find average speed & velocity: a) A→B b) A→C
a) A→B
Distance
= 300 m;Time
= 150 sSpeed
= 300 ÷ 150 = 2.0 m/sVelocity
= 300 ÷ 150 = 2.0 m/sb) A→C
Total distance
= 400 m;Total time
= 210 sSpeed
= 400 ÷ 210 ≃ 1.90 m/sDisplacement
= 200 m;Velocity
= 200 ÷ 210 ≃ 0.95 m/s -
Abdul drives to school at 20 km/h and returns at 30 km/h. What is his average speed for the round trip?
Let one‐way = D km. Time there = D/20 h; back = D/30 h ⇒ total time = D(1/20+1/30) = D/12 h
Total distance
= 2D ⇒Average speed
= 2D ÷ (D/12) = 24 km/h -
A motorboat starts from rest, accelerates at 3 m/s² for 8 s. How far does it travel?
u
=0;a
=3;t
=8s
=ut + ½at² = 0 + 0.5×3×8² = 96 m -
A car at 52 km/h brakes. Shade the area under the speed–time curve for braking. Which part is uniform motion?
The shaded area under the deceleration segment = distance during braking.
The horizontal line at 52 km/h represents uniform motion.
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Fig. 7.10: distance–time graph of A, B, C. a) Who’s fastest? b) Do any meet? c) How far has C gone when B passes A? d) How far has B gone when it passes C?
a) Steepest slope ⇒ fastest.
b) Intersections on the graph show meeting points.
c) Read C’s y‐value at the time B crosses A.
d) Read B’s y‐value at the time B crosses C.
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